What is the magnitude of an electric field that balances the weight of a plastic sphere of mass 6.4 g that has been charged to -3.0 nC? A)2.1 × 10⁷ N/C B)2.4 × 10⁶ N/C C)4.5 × 10⁶ N/C D)6.4 × 10⁶ N/C

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Quizplus · Accepted Answer

The electric force on the sphere is equal to the weight of the sphere, so:$$qE = mg$$where:* q is the charge on the sphere (-3.0 nC)* E is the electric field strength* m is the mass of the sphere (6.4 g)* g is the acceleration due to gravity (9.8 m/s^2)Solving for E, we get:$$E = \frac{mg}{q} = \frac{(6.4 	imes 10^{-3} 	ext{ kg})(9.8 	ext{ m/s}^2)}{-3.0 	imes 10^{-9} 	ext{ C}} = 2.1 	imes 10^7 	ext{ N/C}$$

What Is the Magnitude of an Electric Field That Balances