-A pair of charged conducting plates produces a uniform field of 12,000 N/C,directed to the right,between the plates.The separation of the plates is 40 mm.In the figure,an electron is projected from plate A,directly toward plate B,with an initial velocity of vo = 2.0 × 10⁷ m/s.The velocity of the electron as it strikes plate B is closest to:

Question

Quizplus · Accepted Answer

The electron experiences a force due to the electric field, which causes it to decelerate. Using the work-energy principle, the change in kinetic energy equals the work done by the electric field. The final velocity can be calculated using the equation: v^2 = vo^2 - 2*a*d, where a = eE/m. Solving gives a final velocity of approximately 1.5 × 10^7 m/s.

-A Pair of Charged Conducting Plates Produces a Uniform Field