A package is dropped from a helicopter moving upward at 15 m/s.If it takes 16.0 s before the package strikes the ground,how high above the ground was the package when it was released? (Disregard air resistance. )
A)1000 m
B)1500 m
C)810 m
D)1200 m

Question

Quizplus · Accepted Answer

The package has an initial upward velocity of 15 m/s and an acceleration of -9.8 m/s^2 due to gravity. The time it takes to reach the ground is 16.0 s. We can use the following equation to find the initial height of the package:h = vi*t + 1/2*a*t^2h = 15 m/s * 16.0 s + 1/2*(-9.8 m/s^2)*(16.0 s)^2h = 240 m + 1228.8 mh = 1468.8 mTherefore, the package was released from a height of 1468.8 m above the ground.

A Package Is Dropped from a Helicopter Moving Upward at 15