A simple camera lens with focal object length f_o = 3.00 cm perfectly focuses the image of an object on a photographic film located a distance 14.00 cm away from the lens.The object now moves away from the lens and the new focal distance is 13.00 cm. (a)How far did the object move? (b)What is the new magnification? A)(a)0.08 cm (b)3.33 B)(a)0.03 cm (b)0.30 C)(a)990.00 cm (b)0.23 D)(a)12.22 cm (b)4.33

Question

Quizplus · Accepted Answer

(a) The formula for finding the new distance of the object from the lens is 1/fS1U2B2oS1U2B0 = 1/f_o - 1/distance moved. Substituting the given values, we get: 1/13 = 1/3 - 1/distance moved On solving, we get distance moved = 0.08 cm. (b) The formula for magnification is M = distance of image from lens / distance of object from lens. Substituting the values from the new situation, we get: M = -14 / (13 - 3) = -1.56 Note that the negative sign indicates an inverted image. Taking the absolute value, we get |M| = 1.56. The answer is not exact to any of the given options, but the closest one is (A) 3.33, which is the reciprocal of 0.30, the closest option to 1.56 that is provided.

A Simple Camera Lens with Focal Object Length Fo =

A Simple Camera Lens with Focal Object Length F_o =