A drop of unknown liquid is placed at the point on a glass surface where internal reflection is occurring at θ = 48°.The drop is heated until internal reflection occurs.What is the refractive index of the liquid if n_g= 1.60?

Question

Quizplus · Accepted Answer

The critical angle for total internal reflection is given by θc = sin⁻¹(n₂/n₁), where n₂ is the refractive index of the liquid and n₁ is the refractive index of the glass. Given θc = 48° and n₁ = 1.60, we can solve for n₂: n₂ = n₁ * sin(θc) = 1.60 * sin(48°) ≈ 1.19.

A Drop of Unknown Liquid Is Placed at the Point