Light having a wavelength in vacuum of 600 nm enters a liquid of refractive index 2.0.In this liquid,its wavelength will be:

Question

Quizplus · Accepted Answer

The relationship between the wavelength of light in vacuum and the wavelength of light in a medium is given by:
λ_medium=λ_vacuum/n
where λ_medium is the wavelength of light in the medium, λ_vacuum is the wavelength of light in vacuum and n is the refractive index of the medium.
Substituting the given values, we get:
λ_medium=λ_vacuum/2.0
λ_medium=600 nm/2.0
λ_medium=300 nm
Therefore, the wavelength of light in the given liquid is 300 nm.

Light Having a Wavelength in Vacuum of 600 Nm Enters