Light of wavelength 500 nm illuminates a 0.50 mm diameter hole.A screen is placed 6.0 m behind the slit.What is the width of the central maximum on the screen?

Question

Quizplus · Accepted Answer

The width of the central maximum is given by:$$w = \frac{2\lambda L}{D}$$where:* w is the width of the central maximum* λ is the wavelength of light* L is the distance between the slit and the screen* D is the diameter of the holePlugging in the given values, we get:$$w = \frac{2(500 	imes 10^{-9} 	ext{ m})(6.0 	ext{ m})}{0.50 	imes 10^{-3} 	ext{ m}} = 15 	ext{ mm}$$Therefore, the correct answer is A.

Light of Wavelength 500 Nm Illuminates a 0