A 2.31 kg rope is stretched between supports 10.4 m apart.If one end of the rope is tweaked,how long will it take for the resulting disturbance to reach the other end? Assume that the tension in the rope is 74.4 N.

Question

Quizplus · Accepted Answer

The speed of a wave on a string is given by v = sqrt(T/m), where T is the tension in the string and m is the mass per unit length of the string. In this case, T = 74.4 N and m = 2.31 kg / 10.4 m = 0.222 kg/m. Therefore, v = sqrt(74.4 N / 0.222 kg/m) = 23.7 m/s. The time it takes for the disturbance to reach the other end of the rope is then t = d/v = 10.4 m / 23.7 m/s = 0.568 s.

A 231 Kg Rope Is Stretched Between Supports 10