-A pressurized cylindrical tank,5.0 m in diameter,contains water that emerges from the pipe at point C,with a velocity of 13 m/s.Point A is 10 m above point B and point C is 3 m above point B.The area of the pipe at point B is 0.08 m² and the pipe narrows to an area of 0.04 m² at point C.Assume the water is an ideal fluid in laminar flow.The density of water is 1000 kg/m³.In the figure,the mass flow rate in the pipe is closest to:

Question

Quizplus · Accepted Answer

The mass flow rate is calculated using the formula: mass flow rate = density × velocity × area. At point C, the velocity is 13 m/s and the area is 0.04 m². Therefore, mass flow rate = 1000 kg/m³ × 13 m/s × 0.04 m² = 520 kg/s.

-A Pressurized Cylindrical Tank,5