A Carnot engine operates between two reservoirs with unknown temperatures.If the Carnot engine operates at 43% efficiency,what is the ratio of the kelvin temperatures of the reservoirs,T_c/T_h? A)0.57 B)0.0021 C)0.0016 D)0.42999999

Question

Quizplus · Accepted Answer

The efficiency of a Carnot engine is given by:
Efficiency = (T2-T1)/T2

where T1 and T2 are the temperatures of the two reservoirs in Kelvin scale. We can rearrange this equation to get the ratio of temperatures:

T1/T2 = 1 - (Efficiency/100)

Substituting the given efficiency of 43%, we get:
T1/T2 = 1 - 0.43 = 0.57

Therefore, the ratio of Kelvin temperatures of the reservoirs is 0.57, which corresponds to choice A.

A Carnot Engine Operates Between Two Reservoirs with Unknown Temperatures