A 2.0 kg stone slides from rest down a hill 5.0 m high and is observed to be moving at 6.0 m/s at the bottom.During this process,62 J of thermal energy have been produced.

Question

Quizplus · Accepted Answer

The conservation of energy principle tells us that the gravitational potential energy at the top of the hill is converted to kinetic energy at the bottom, neglecting air resistance. Using the formula for gravitational potential energy (PE=mgh), we have PE = (2.0 kg)(9.8 m/s^2)(5.0 m) = 98 J. This means that the initial potential energy is converted to kinetic energy, given by KE = (1/2)mv^2 = (1/2)(2.0 kg)(6.0 m/s)^2 = 36 J. The difference between the initial potential energy and final kinetic energy is the amount of energy that is dissipated as thermal energy, which is 98 J - 36 J = 62 J. Therefore, the statement is true.

A 20 Kg Stone Slides from Rest Down a Hill 5