Suppose that the Blood Alcohol Content (BAC) of students who drink five beers varies from student to student according to a Normal distribution with mean 0.07 and standard deviation 0.01.
Julie is administered a BAC test and told she scored 0.085. Her standard score is:
A)100.
B)150.
C)15.
D) 1.5.
E) 0.15.

Question

Quizplus · Accepted Answer

The standard score (z-score) for a value x from a Normal distribution with mean μ and standard deviation σ is given by:

z = (x - μ)/σ

In this case, Julie's BAC score is x = 0.085, the mean BAC for students who drink five beers is μ = 0.07, and the standard deviation is σ = 0.01.

Plugging these values into the formula, we get:

z = (0.085 - 0.07)/0.01 = 1.5

Therefore, Julie's standard score is 1.5.

Suppose That the Blood Alcohol Content (BAC) of Students Who