Instruction 9-6
The quality control engineer for a furniture manufacturer is interested in the mean amount of force necessary to produce cracks in stressed oak furniture. She performs a two-tailed test of the null hypothesis that the mean for the stressed oak furniture is 650. The calculated value of the Z test statistic is a positive number that leads to a p-value of 0.080 for the test.
-Referring to Instruction 9-6,if the test is performed with a level of significance of 0.05,the null hypothesis would be rejected.

Question

Quizplus · Accepted Answer

The p-value of the test (0.080) is greater than the level of significance (0.05), indicating that we fail to reject the null hypothesis. Therefore, the statement "if the test is performed with a level of significance of 0.05, the null hypothesis would be rejected" is false.

Instruction 9-6 The Quality Control Engineer for a Furniture Manufacturer Is Interested