What is output by the following Java code segment? int temp = 180; While ( temp != 80 ) { If ( temp 90 ) { System.out.print( "This porridge is too hot! " ); // cool down Temp = temp - ( temp 150 ? 100 : 20 ); } // end if Else { If ( temp

Question

What is output by the following Java code segment? int temp = 180;
While ( temp != 80 )
{
If ( temp > 90 )
{
System.out.print( "This porridge is too hot! " ) ;
// cool down
Temp = temp - ( temp > 150 ? 100 : 20 ) ;
} // end if
Else
{
If ( temp < 70 )
{
System.out.print(
"This porridge is too cold! ") ;
// warm up
Temp = temp + (temp < 50 ? 30 : 20) ;
} // end if
} // end else
} // end while
If ( temp == 80 )
System.out.println( "This porridge is just right!" ) ;

Quizplus · Accepted Answer

The while loop keeps executing as long as temp is not equal to 80. Inside the loop, if temp is above 90, the output is "This porridge is too hot!" and temp is cooled down by either 100 or 20 degrees. If temp is below 70, the output is "This porridge is too cold!" and temp is warmed up by either 30 or 20 degrees. Eventually, temp will reach 80 and the loop will exit. At that point, the output will be "This porridge is just right!"

What Is Output by the Following Java Code Segment? Int