An electrical engineer wants to compare the resistance of four types of wire made from different materials.Five wires of equal lengths and cross sectional areas are prepared for each of the four wire types.Each section of wire is randomly tested by sending a current through the wire and measuring the resistance.After collecting the data and analyzing the results,she reports that the F-ratio is 1.076.Assuming that the conditions required for ANOVA are satisfied,what is the P-value? What would you conclude?
A)p = 0.0871.Do not reject H0 using α = 0.05.
B)p = 0.3872.Do not reject H0 using α = 0.05.
C)p = 0.0871.Reject H0 using α = 0.10.
D)p = 0.3872.Reject H0 using α = 0.05.
E)p = 0.3872.Reject H0 using α = 0.25.

Question

Quizplus · Accepted Answer

To find the P-value, we need to use an F-distribution table with the degrees of freedom (df) of numerator and denominator. The numerator df is 3 (number of groups - 1) and the denominator df is 16 (total sample size - number of groups). Using the table, we find the P-value to be approximately 0.3872. 
Since the P-value is greater than the significance level α of 0.05, we do not reject the null hypothesis that there is no significant difference in resistance between the four types of wire. We conclude that there is not enough evidence to conclude that the mean resistance of any wire types differ significantly from one another.

An Electrical Engineer Wants to Compare the Resistance of Four