The two-way table summarizes data from the human resource department at a university: New Hires $$\begin{array} { l | c c | c }
& \text { Tenure } & \text { Adjunct } & \text { Total } \
\hline \text { Men } & 17 & 25 & 42 \
\text { Women } & 20 & 21 & 41 \
\hline \text { Total } & 37 & 46 & 83
\end{array}$$ What is the probability (rounded to two decimal places)of a randomly selected new hire being tenure track given that the new hire is a woman?
A)0
B)0.51
C)0.49
D)0.20
E)0.24

Question

The two-way table summarizes data from the human resource department at a university: New Hires $$\begin{array} { l | c c | c } 
& \text { Tenure } & \text { Adjunct } & \text { Total } \
\hline \text { Men } & 17 & 25 & 42 \
\text { Women } & 20 & 21 & 41 \
\hline \text { Total } & 37 & 46 & 83
\end{array}$$ What is the probability (rounded to two decimal places)of a randomly selected new hire being tenure track given that the new hire is a woman?
A)0
B)0.51
C)0.49
D)0.20
E)0.24

Quizplus · Accepted Answer

To find the probability of a randomly selected new hire being tenure track given that they are a woman, we need to look at the female row in the table. Out of the 40 new female hires, 20 are tenure track. So the probability is 20/40 = 0.5 or 50%. Rounded to two decimal places, this is 0.49, which is closest to answer choice C.

The Two-Way Table Summarizes Data from the Human Resource Department