A sample of 51 statistics students at a large university had a mean final exam score of 76 with a standard deviation of 4.Find a 95% confidence interval for the mean final exam score for all statistics students at this university.

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Quizplus · Accepted Answer

Using the formula for a confidence interval for the mean, we have: CI = x̄ ± (z * (σ/√n)), where x̄ is the sample mean, σ is the standard deviation, n is the sample size, and z is the z-score corresponding to the desired confidence level. For a 95% confidence level, the z-score is approximately 1.96. Plugging in the given values: CI = 76 ± (1.96 * (4/√51)). This calculation results in the interval (74.9, 77.1).

A Sample of 51 Statistics Students at a Large University