A poll reported that 41 of 100 men surveyed were in favour of increased security at airports,while 35 of 140 women were in favour of increased security.
A)P-value = 0.0512; If there is no difference in the proportions,there is about a 5.12% chance of seeing the observed difference or larger by natural sampling variation.
B)P-value = 0.0512; There is about a 5.12% chance that the two proportions are equal.
C)P-value = 0.4211; If there is no difference in the proportions,there is a 42.11% chance of seeing the exact observed difference by natural sampling variation.
D)P-value = 0.0086; There is about a 0.86% chance that the two proportions are equal.
E)P-value = 0.0086; If there is no difference in the proportions,there is about a 0.86% chance of seeing the observed difference or larger by natural sampling variation.

Question

Quizplus · Accepted Answer

The p-value is the probability of observing a difference as extreme or more extreme than the one observed, assuming the null hypothesis is true. In this case, the null hypothesis is that there is no difference in the proportion of men and women in favor of increased security at airports. The observed difference is (41/100) - (35/140) = 0.06. Using a two-sample z-test, the calculated p-value is 0.0086. This means that, if there is no difference in the proportions, there is about a 0.86% chance of observing a difference as extreme or more extreme than 0.06 by natural sampling variation. Therefore, the best choice is E.

A Poll Reported That 41 of 100 Men Surveyed Were