A new manager started a program on employee sick leave.The manager later compares the sick leave rate prior to the program starting (65 out of 250 employees were sick)to the sick leave rate one month into the program (55 out of 253 employees were sick).
A)P-value = 0.1314; There is about a 13.14% chance that the two proportions are equal.
B)P-value = 0.2628; There is about a 26.28% chance that the two proportions are equal.
C)P-value = 0.7372; If there is no difference in the proportions,there is about a 73.72% chance of seeing the observed difference or larger by natural sampling variation.
D)P-value = 0.1314; If there is no difference in the proportions,there is about a 13.14% chance of seeing the observed difference or larger by natural sampling variation.
E)P-value = 0.2628; If there is no difference in the proportions,there is about a 26.28% chance of seeing the observed difference or larger by natural sampling variation.

Question

Quizplus · Accepted Answer

The P-value of 0.2628 indicates that if there is no actual difference in the proportions, there is about a 26.28% chance of observing the difference seen or a more extreme one due to random sampling variation.

A New Manager Started a Program on Employee Sick Leave