A survey found that 79% of a random sample of 1024 Canadian adults approved of cloning endangered animals.Find the margin of error for this survey if we want 90% confidence in our estimate of the percent of Canadian adults who approve of cloning endangered animals.
A)4.56%
B)21.4%
C)5.43%
D)2.49%
E)2.09%

Question

Quizplus · Accepted Answer

The margin of error (ME) for a proportion can be calculated using the formula: $ME = Z * \sqrt{\frac{p(1-p)}{n}}$, where $Z$ is the Z-score corresponding to the desired confidence level, $p$ is the sample proportion, and $n$ is the sample size. For a 90% confidence level, the Z-score is approximately 1.645. Given $p = 0.79$ and $n = 1024$, the calculation is as follows: $ME = 1.645 * \sqrt{\frac{0.79(1-0.79)}{1024}}$, which equals approximately 0.0209 or 2.09%.

A Survey Found That 79% of a Random Sample of 1024