Suppose that 10% of people are left handed.If 5 people are selected at random,what is the probability that exactly 2 of them are left handed?
A)0.1458
B)0.0729
C)0.0100
D)0.0073
E)0.0081

Question

Quizplus · Accepted Answer

This is a binomial distribution problem with n=5 and p=0.1. The probability of exactly 2 out of 5 being left-handed is given by the binomial probability function:

P(X=2) = (5 choose 2) * (0.1)^2 * (0.9)^3

where (5 choose 2) = 10 is the number of ways to select 2 items out of 5. Plugging in the values, we get:

P(X=2) = 10 * (0.1)^2 * (0.9)^3
P(X=2) = 0.0729

Therefore, the answer is B.

Suppose That 10% of People Are Left Handed