A consumer organization estimates that 35% of the households in a particular community have one television set,39% have two sets,and 16% have three or more sets.If two independent households are chosen at random,what is the probability that at least one has one or more television sets?
A)0.180
B)0.990
C)0.810
D)0.010
E)0.900

Question

Quizplus · Accepted Answer

The probability that at least one household has one or more television sets can be found by subtracting the probability that neither household has a television set from 1. Since 10% of households have no television set (100% - 90% of households with one or more sets), the probability that a randomly chosen household does not have a television set is 0.10. Therefore, the probability that two randomly chosen households both do not have a television set is 0.10 * 0.10 = 0.01. Subtracting this from 1 gives 1 - 0.01 = 0.99, which is the probability that at least one of the two households has one or more television sets.

A Consumer Organization Estimates That 35% of the Households in a Particular