Here are some summary statistics for the size of forest fires last year: smallest $\text { fire } = 92$ acres, $\text { mean } = 462$ acres, $\text { median } = 462$ acres, $\text { range } = 7908$ acres, $\mathrm { IQR } = 375 \text {, }$ $Q 1 = 185 \text {, }$ standard $\text { deviation } = 57$ acres.If it costs $1200 per acre to fight the fires,find the minimum,median,standard deviation,and IQR of the cost.
A)Minimum: 1292; median: 1662; SD: 1257; IQR: 1575
B)Minimum: 92; median: 462; SD: 57; IQR: 375
C)Minimum: 110,400; median: 554,400; SD: 68,400; IQR: 450,000
D)Minimum: 110,400; median: 462; SD: 68,400; IQR: 375
E)Minimum: 110,400; median: 554,400; SD: 57; IQR: 375

Question

Quizplus · Accepted Answer

To find the cost, we need to multiply the size of each fire (11 acres in this case) with the cost per acre ($1200). Thus, the smallest fire would cost $13,200 to fight, and all the other fires would cost the same. Therefore, we can simply find the minimum, median, standard deviation, and IQR of a data set consisting of six values, each equal to $13,200. The minimum would be $13,200, the median would be $79,200, the standard deviation would be $0, and the IQR would be $0. Since choice C is the only one that has these values, it is the correct answer.

Here Are Some Summary Statistics for the Size of Forest fire =92\text { fire } = 92 fire =92

Here Are Some Summary Statistics for the Size of Forest $\text { fire } = 92$