Solve the equation. $2 y ^ { 2 } - 3 y - 3 = 0$
A) $y = \frac { 3 } { 4 } \pm \sqrt { 33 }$
B) $y = \frac { - 3 \pm \sqrt { 33 } } { 6 }$
C) $y = \frac { \sqrt { 35 } \pm 3 } { 2 }$
D) $y = \frac { 3 \pm \sqrt { 35 } } { 3 }$
E) $y = \frac { 3 \pm \sqrt { 33 } } { 4 }$

Question

Quizplus · Accepted Answer

The Answer is E

Solve the Equation 2y2−3y−3=02 y ^ { 2 } - 3 y - 3 = 02y2−3y−3=0

Solve the Equation $2 y ^ { 2 } - 3 y - 3 = 0$