Which of the following lines would be the prototype for an overloaded cast operator function that converts an object of user-defined type Time into a double?
A) Time::operator double() const;
B) Time::static_cast double() const;
C) Time::operator_cast(double) const;
D) Time::double() const;

Question

Quizplus · Accepted Answer

The prototype for an overloaded cast operator function is in the format of "operator conversion-type-id", where the conversion-type-id is the type to which the object will be converted. In this case, we want to convert a Time object to a double, so the prototype should be "operator double()". The "const" keyword is added to indicate that the function will not modify the object being converted. Choice B is incorrect because static_cast is not used for defining overloaded cast operators. Choice C is not a valid syntax for defining a cast operator. Choice D does not follow the correct syntax for defining overloaded cast operator functions.

Which of the Following Lines Would Be the Prototype for an Overloaded