Given that x = 2, y = 1, and z = 0, what will the following cout statement display? cout

Name: Given that x = 2, y = 1, and z = 0, what will the following cout statement display? cout << "answer = " << (x || !y && z) << endl; A) answer = 0 B) answer = 1 C) answer = 2 D) None of these
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Question

Given that x = 2, y = 1, and z = 0, what will the following cout statement display? cout << "answer = " << (x || !y && z) << endl;
A) answer = 0
B) answer = 1
C) answer = 2
D) None of these

Quizplus · Accepted Answer

The expression (x || !y && z) evaluates to true (1) because x is 2 (non-zero, hence true), making the entire OR expression true regardless of the other operands.

Given That X = 2, Y = 1, and Z