What will the following code output? int number = 22;
Int *var = &number;
Cout

Question

What will the following code output? int number = 22;
Int *var = &number;
Cout << *var << endl;
A) The address of the number variable
B) 22
C) An asterisk followed by 22
D) An asterisk followed by the address of the number variable

Quizplus · Accepted Answer

The code declares an integer variable named "number" and initializes it to 22. Then a pointer variable named "var" is declared and assigned the memory address of "number" using the & operator. Finally, the value stored in the memory location pointed to by "var" is printed using the * operator, which results in the value of "number" being printed, i.e., 22. Therefore, the correct answer is B, which is the value of the "number" variable.

What Will the Following Code Output? Int Number = 22;