Find the equation of the tangent line to f (x)= ln x + 2 at x = 1.
A)y = 1
B)x = 1
C)y = x + 1
D)y = x

Name: Find the equation of the tangent line to f (x)= ln x + 2 at x = 1. A)y = 1 B)x = 1 C)y = x + 1 D)y = x
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Question

Quizplus · Accepted Answer

The derivative of $f(x) = \ln(x) + 2$ is $f'(x) = \frac{1}{x}$. At $x = 1$, $f'(1) = 1$, so the slope of the tangent line is 1. Since $f(1) = \ln(1) + 2 = 2$, the equation of the tangent line is $y - 2 = 1(x - 1)$, which simplifies to $y = x + 1$.

Find the Equation of the Tangent Line to F (X)=