An object moving in a straight line has velocity $v ( t ) = t e ^ { \sqrt { t } }$ meters per second.Is it true that in the first 4 seconds the object will have travelled $4 e ^ { 2 } + 12$ meters?

Question

Quizplus · Accepted Answer

To find the distance traveled, we need to integrate the velocity function from 0 to 4. The integral of $v(t) = t e^{\sqrt{t}}$ from 0 to 4 does not equal $4 e^2 + 12$.

An Object Moving in a Straight Line Has Velocity v(t)=tetv ( t ) = t e ^ { \sqrt { t } }v(t)=tet​

An Object Moving in a Straight Line Has Velocity $v ( t ) = t e ^ { \sqrt { t } }$