Write a differential equation describing the given situation.Define all variables you introduce.(Do not try to solve the differential equation at this time.)An investment grows at a rate of 3% of its size.
A)Let Q denote the investment and let t denote time; $\frac { d Q } { d t } = 0.03 Q$
B)Let Q denote the investment and let t denote time; $\frac { d Q } { d t } = 0.03 t$
C)Let Q denote the investment and let t denote time; $\frac { d Q } { d t } = 0.3 Q$
D)Let Q denote the investment and let t denote time; $\frac { d Q } { d t } = 3 Q$

Question

Quizplus · Accepted Answer

The correct differential equation is $\frac { d Q } { d t } = 0.03 Q$, which states that the rate of change of the investment, $Q$, with respect to time, $t$, is proportional to its current size, with a growth rate of 3% (or 0.03 in decimal form).

Write a Differential Equation Describing the Given Situation dQdt=0.03Q\frac { d Q } { d t } = 0.03 QdtdQ​=0.03Q

Write a Differential Equation Describing the Given Situation $\frac { d Q } { d t } = 0.03 Q$