Determine the domain of the given function. $f ( x ) = \frac { x ^ { 2 } - 1 } { x + 3 }$
A)all real numbers x except x = 1,x = -1,and x = -3
B)all real numbers x
C)all real numbers x except x = -3
D)all real numbers x except x = 1 and x = 4

Question

Quizplus · Accepted Answer

The domain of $f(x) = \frac{x^2 - 1}{x + 3}$ is all real numbers except where the denominator equals zero. The denominator is zero when $x + 3 = 0$, which gives $x = -3$. Thus, the domain excludes $x = -3$ only.

Determine the Domain of the Given Function f(x)=x2−1x+3f ( x ) = \frac { x ^ { 2 } - 1 } { x + 3 }f(x)=x+3x2−1​

Determine the Domain of the Given Function $f ( x ) = \frac { x ^ { 2 } - 1 } { x + 3 }$