Suppose in a study of a prarie dog town it is discovered that the number of prarie dogs at any time t is given by $\mathrm { P } ( \mathrm { t } ) = 1000 + 500 \cos \left( \frac { 2 \pi \mathrm { t } } { 12 } \right)$ , where t is measured in months from July 1, 1990. What is the average number of prarie dogs living in the town from July 1, 1990 to July 1, 1992?
Enter just an integer.

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The Answer of Suppose in a study of a prarie dog town it is discovered that the number of prarie dogs at any time t is given by $\mathrm { P } ( \mathrm { t } ) = 1000 + 500 \cos \left( \frac { 2 \pi \mathrm { t } } { 12 } \right)$ , where t is measured in months from July 1, 1990. What is the average number of prarie dogs living in the town from July 1, 1990 to July 1, 1992?
Enter just an integer.

Suppose in a Study of a Prarie Dog Town It P(t)=1000+500cos⁡(2πt12)\mathrm { P } ( \mathrm { t } ) = 1000 + 500 \cos \left( \frac { 2 \pi \mathrm { t } } { 12 } \right)P(t)=1000+500cos(122πt​)

Suppose in a Study of a Prarie Dog Town It $\mathrm { P } ( \mathrm { t } ) = 1000 + 500 \cos \left( \frac { 2 \pi \mathrm { t } } { 12 } \right)$