Compute $\frac { \mathrm { dy } } { \mathrm { dx } }$ y = 4 $u ^ { 2 }$ + 8u + 4 and u = 3x + 1.
Enter your answer as just a polynomial in x in standard form (no label).

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The Answer of Compute $\frac { \mathrm { dy } } { \mathrm { dx } }$ y = 4 $u ^ { 2 }$ + 8u + 4 and u = 3x + 1.
Enter your answer as just a polynomial in x in standard form (no label).

Compute dydx\frac { \mathrm { dy } } { \mathrm { dx } }dxdy​

Compute $\frac { \mathrm { dy } } { \mathrm { dx } }$