Given $y ^ { \prime }$ = y(y + 3). On a ty-coordinate system sketch the solutions corresponding to the initial conditions $y ( 0 ) = - 4$ , $y ( 0 ) = - 1$ , and $y ( 0 ) = 1$ . Does this graph represent the situation?

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The Answer of Given $y ^ { \prime }$ = y(y + 3). On a ty-coordinate system sketch the solutions corresponding to the initial conditions $y ( 0 ) = - 4$ , $y ( 0 ) = - 1$ , and $y ( 0 ) = 1$ . Does this graph represent the situation?

Given y′y ^ { \prime }y′ = Y(y + 3) y(0)=−4y ( 0 ) = - 4y(0)=−4

Given $y ^ { \prime }$ = Y(y + 3) $y ( 0 ) = - 4$