Differentiate.
-f(x) = 2 $x ^ { 4 }$ + 5 $x ^ { 3 }$ + 6
A) f'(x) = 4 $x ^ { 3 }$ + 3 $x ^ { 2 }$
B) f'(x) = 4 $x ^ { 3 }$ + 3 $x ^ { 2 }$ - 7
C) f'(x) = 8 $x ^ { 3 }$ + 15 $x ^ { 2 }$ - 7
D) f'(x) = 8 $x ^ { 3 }$ + 15 $x ^ { 2 }$

Question

Quizplus · Accepted Answer

The derivative of $f(x) = 2x^4 + 5x^3 + 6$ is found by applying the power rule to each term: $f'(x) = 8x^3 + 15x^2$. The constant term 6 differentiates to 0.

Differentiate x4x ^ { 4 }x4 + 5 x3x ^ { 3 }x3

Differentiate $x ^ { 4 }$ + 5 $x ^ { 3 }$