A rock is thrown off a cliff. Its distance from the ground below at t seconds is $s ( t ) = - 16 t ^ { 2 } + 16 t + 96$ feet. What is the velocity after 1 second?
Enter just an integer. No units.

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The Answer of A rock is thrown off a cliff. Its distance from the ground below at t seconds is $s ( t ) = - 16 t ^ { 2 } + 16 t + 96$ feet. What is the velocity after 1 second?
Enter just an integer. No units.

A Rock Is Thrown Off a Cliff s(t)=−16t2+16t+96s ( t ) = - 16 t ^ { 2 } + 16 t + 96s(t)=−16t2+16t+96

A Rock Is Thrown Off a Cliff $s ( t ) = - 16 t ^ { 2 } + 16 t + 96$