An object starts from rest at time t = 0.00 s and moves in the +x direction with constant acceleration. The object travels 12.0 m from time t = 1.00 s to time t = 2.00 s. What is the acceleration of the object? A) -12.0 m/s² B) 24.0 m/s² C) -4.00 m/s² D) 4.00 m/s² E) 8.00 m/s²

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Quizplus · Accepted Answer

The displacement from t = 1.00 s to t = 2.00 s is given by the equation: s = ut + 0.5at^2. Since the object starts from rest, u = 0. The displacement is 12.0 m, and the time interval is 1 s. Solving 12 = 0.5a(1)^2 gives a = 24 m/s^2. However, this is the total acceleration over the entire time, so the correct acceleration is 8.00 m/s^2.

An Object Starts from Rest at Time T = 0