A small boat is moving at a velocity of 3.35 m/s when it is accelerated by a river current perpendicular to the initial direction of motion. If the acceleration of the current is 0.750 m/s², what will be the new velocity of the boat after 33.5 s? A) 25.3 m/s at 82.4° from initial direction of motion B) 25.3 m/s at 7.59° from initial direction of motion C) 640.1 m/s at 82.4° from initial direction of motion D) 640.1 m/s at 7.59° from initial direction of motion

Question

Quizplus · Accepted Answer

The new velocity in the direction of the current is given by v = at = 0.750 m/s² * 33.5 s = 25.125 m/s. The resultant velocity is found using the Pythagorean theorem: √(3.35² + 25.125²) ≈ 25.3 m/s. The angle θ is given by tan⁻¹(25.125/3.35) ≈ 82.4°.

A Small Boat Is Moving at a Velocity of 3