An object weighing 4.00 N falls from rest subject to a frictional drag force given by Fdrag = bv², where v is the speed of the object and b = 3.00 N · s²/m². What terminal speed will this object approach? A) 1.78 m/s B) 3.42 m/s C) 1.15 m/s D) 2.25 m/s E) 0.75 m/s

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Quizplus · Accepted Answer

At terminal speed, the gravitational force equals the drag force: 4.00 N = 3.00 N·s²/m² * v². Solving for v gives v = sqrt(4.00/3.00) = 1.15 m/s.

An Object Weighing 4