What is the period (in hours) of a satellite circling Mars 100 km above the planet's surface? The mass of Mars is 6.42 × 10²³ kg, its radius is 3.40 × 10⁶ m, and G = 6.67 × 10^-11 N ∙ m²/kg². A) 1.75 h B) 1.25 h C) 1.15 h D) 1.00 h E) 1.45 h

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The period of a satellite circling a planet is given by:$$T = 2\pi \sqrt{\frac{r^3}{GM}}$$where r is the distance from the center of the planet to the satellite, G is the gravitational constant, and M is the mass of the planet.Plugging in the given values, we get:$$T = 2\pi \sqrt{\frac{(3.40 	imes 10^6 m + 100 km)^3}{(6.67 	imes 10^{-11} N \cdot m^2/kg^2)(6.42 	imes 10^{23} kg)}}$$$$T = 1.75 h$$

What Is the Period (In Hours) of a Satellite Circling