Find the orbital speed of an ice cube in the rings of Saturn. The mass of Saturn is 5.68 × 1026 kg and the rings have an average radius of 100,000 km. (G = 6.67 × 10^-11 N ∙ m²/kg²) A) 19.5 km/s B) 27.5 km/s C) 13.8 km/s D) 1.95 km/s

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The orbital speed of an object is given by:$$v = \sqrt{\frac{GM}{r}}$$where:* v is the orbital speed in m/s* G is the gravitational constant in N ∙ m2/kg2* M is the mass of the object in kg* r is the radius of the orbit in mIn this case, we have:* G = 6.67 × 10-11 N ∙ m2/kg2* M = 5.68 × 1026 kg* r = 100,000 km = 100,000,000 mPlugging these values into the equation, we get:$$v = \sqrt{\frac{(6.67 	imes 10^{-11} N \cdot m^2/kg^2)(5.68 	imes 10^{26} kg)}{100,000,000 m}} = 19.5 km/s$$Therefore, the orbital speed of an ice cube in the rings of Saturn is 19.5 km/s.

Find the Orbital Speed of an Ice Cube in the Rings