The position of an object that is oscillating on an ideal spring is given by the equation x = (12.3 cm) cos[(1.26s^-1)t]. At time t = 0.815 s,
(a) how fast is the object moving?
(b) what is the magnitude of the acceleration of the object?

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The Answer of The position of an object that is oscillating on an ideal spring is given by the equation x = (12.3 cm) cos[(1.26s^-1)t]. At time t = 0.815 s, (a) how fast is the object moving? (b) what is the magnitude of the acceleration of the object?

The Position of an Object That Is Oscillating on an Ideal