A 648-g empty iron kettle is put on a stove. How much heat, in joules, must it absorb to raise its temperature from 15.0°C to 37.0°C? (The specific heat for iron is 113 cal/kg•C°, 1 cal = 4.190 J)
A) 6740 J
B) 11,300 J
C) 1610 J
D) 16,100 J

Question

Quizplus · Accepted Answer

The correct answer is A.The amount of heat required to raise the temperature of an object is given by the equation:Q = mcΔTwhere Q is the heat energy in joules, m is the mass of the object in kilograms, c is the specific heat capacity of the object in joules per kilogram per degree Celsius, and ΔT is the change in temperature in degrees Celsius.In this problem, we have:m = 648 g = 0.648 kgc = 113 cal/kg•C° = 473 J/kg•C°ΔT = 37.0°C - 15.0°C = 22.0°CSubstituting these values into the equation, we get:Q = (0.648 kg)(473 J/kg•C°)(22.0°C) = 6740 JTherefore, the amount of heat required to raise the temperature of the kettle from 15.0°C to 37.0°C is 6740 J.

A 648-G Empty Iron Kettle Is Put on a Stove