A steel container,equipped with a piston,contains 21 mol of an ideal gas at 465 K.The container is compressed isothermally to 90% of its original volume.How much work is done on the gas? The ideal gas constant is R = 8.314 J/mol • K.

Question

Quizplus · Accepted Answer

The work done on the gas during an isothermal compression can be calculated using the formula W = -nRT ln(Vf/Vi). Here, n = 21 mol, R = 8.314 J/mol•K, T = 465 K, and Vf/Vi = 0.9. Plugging in these values gives W = -21 * 8.314 * 465 * ln(0.9) ≈ 8600 J.

A Steel Container,equipped with a Piston,contains 21 Mol of an Ideal