The electric field 1.5 cm from a very small charged object points toward the object with a magnitude of 180,000 N/C. What is the charge on the object? (k = 1/4πε0 = 8.99 × 10⁹ N ∙ m²/C²)

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The electric field points toward the object, indicating a negative charge. Using the formula E = k|q|/r², we solve for q: q = Er²/k. Substituting E = 180,000 N/C, r = 0.015 m, and k = 8.99 × 10⁹ N∙m²/C², we find q ≈ -4.5 nC.

The Electric Field 1