An electric field is set up between two parallel plates, each of area 2.0 m², by putting 1.0 μC of charge on one plate and -1.0 μC of charge on the other. The plates are separated by 4.0 mm with their centers opposite each other, and the charges are distributed uniformly over the surface of the plates. What is the magnitude of the electric field between the plates at a distance of 1.0 mm from the positive plate, but not near the edges of the plates? (ε0 = 8.85 × 10^-12C²/N ∙ m²)

Question

Quizplus · Accepted Answer

The electric field between two parallel plates is given by E = σ/ε0, where σ is the surface charge density. σ = Q/A = 1.0 μC / 2.0 m² = 5.0 × 10⁻⁷ C/m². Thus, E = (5.0 × 10⁻⁷ C/m²) / (8.85 × 10⁻¹² C²/N·m²) = 5.6 × 10⁴ N/C.

An Electric Field Is Set Up Between Two Parallel Plates