A very large sheet of a conductor carries a uniform charge density of 4.00 pC/mm²on its surfaces. What is the electric field strength 3.00 mm outside the surface of the conductor? (ε₀ = 8.85 × 10^-12 C²/N ∙ m²)

Question

Quizplus · Accepted Answer

The electric field strength outside a charged conductor is given by E = σ/2ε₀, where σ is the charge density and ε₀ is the permittivity of free space. Plugging in the given values, we get E = (4.00 pC/mm²) / (2 * 8.85 × 10^-12 C²/N ∙ m²) = 4.52 × 10⁵ N/C.

A Very Large Sheet of a Conductor Carries a Uniform