If an electron is accelerated from rest through a potential difference of 9.9 kV, what is its resulting speed? (e = 1.60 × 10^-19C, k = 1/4πε₀ = 8.99 × 10⁹ N ∙ m²/C², mel = 9.11 x 10^-31 kg)

Question

Quizplus · Accepted Answer

The kinetic energy gained by the electron is equal to the work done on it by the electric field, which is eV. Using the equation 0.5 * m * v^2 = eV, we can solve for v: v = sqrt(2 * e * V / m). Substituting the given values, v = sqrt(2 * 1.60 × 10^-19 C * 9.9 × 10^3 V / 9.11 × 10^-31 kg) ≈ 5.9 × 10^7 m/s.

If an Electron Is Accelerated from Rest Through a Potential