An electron enters a magnetic field of 0.75 T with a velocity perpendicular to the direction of the field. At what frequency does the electron traverse a circular path? (mel = 9.11 × 10^-31 kg, e = 1.60 × 10^-19 C) A) 2.1 × 10¹⁰Hz B) 4.8 × 10^-7 Hz C) 2.1 × 10¹⁴ Hz D) 4.8 × 10^-11 Hz

Question

Quizplus · Accepted Answer

The frequency of an electron moving in a magnetic field is given by the cyclotron frequency formula: f = (eB)/(2πm). Substituting the given values: f = (1.60 × 10^-19 C × 0.75 T) / (2π × 9.11 × 10^-31 kg) ≈ 2.1 × 10^10 Hz.

An Electron Enters a Magnetic Field of 0