A wire carrying a current is shaped in the form of a circular loop of radius 3.0 mm. If the magnetic field strength that this current produces at the center of the loop is 1.1 mT, what is the magnitude of the current that flows through the wire? (μ0 = 4π × 10^-7 T ∙ m/A) A) 5.3 A B) 16 A C) 9.1 A D) 23 A

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Quizplus · Accepted Answer

The magnetic field strength at the center of a circular loop of wire is given by:B = (μ0 * I) / (2 * π * r)where:B is the magnetic field strength (in teslas)μ0 is the permeability of free space (4π × 10^-7 T ∙ m/A)I is the current (in amperes)r is the radius of the loop (in meters)We are given that:B = 1.1 mT = 1.1 × 10^-3 Tr = 3.0 mm = 3.0 × 10^-3 mSubstituting these values into the equation, we get:1.1 × 10^-3 T = (4π × 10^-7 T ∙ m/A) * I / (2 * π * 3.0 × 10^-3 m)Solving for I, we get:I = 5.3 ATherefore, the magnitude of the current that flows through the wire is 5.3 A.

A Wire Carrying a Current Is Shaped in the Form